Float string to integer string

Question

I have a float in the String strFloat. I wanted to convert it to a rounded integer also stored in a String. This looks awful to me, so please offer some suggestions for improvement.

String strInteger = new Integer(Float.valueOf(strFloat).intValue()).toString()

Answer 1

Instead of creating a new Integer and throwing it away, use String.valueOf() directly.

String strInteger = String.valueOf(Float.valueOf(strFloat).intValue())

Answer 2

If your float is already a String then you definitely should go with BigDecimal. Creating a real intermediate float only add inaccuracy.

String strInteger = new BigDecimal(strFloat).toBigInteger().toString());

Of course you can take advantage of all the arithmetic power of BigDecimal and define a specific rounding mode etc.

EDIT: Just to prove that the float approach will fail (tested in Java 6):

Float.valueOf( "1.99999999" ).intValue()==2 
Float.valueOf( "2.9999999" ).intValue()==3
Float.valueOf( "393650.99" ).intValue()==393651
Float.valueOf( "2545818.9" ).intValue()==2545819
(and many more)