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Nov 18, 2020 at 15:35 answer added Serge Ballesta timeline score: 1
Nov 18, 2020 at 15:33 vote accept Pedro
Nov 18, 2020 at 15:31 comment added Tomerikoo That big if doesn't evaluate as you want it to. A more Pythonic way to express that condition is: if not all(tab[i][j] in (1, -1, 0) for i in range(3) for j in range(3))
Nov 18, 2020 at 15:31 history reopened Serge Ballesta python
Nov 18, 2020 at 15:30 history closed Tomerikoo
tripleee python
Duplicate of Why does "a == x or y or z" always evaluate to True? How can I compare "a" to all of those?
Nov 18, 2020 at 15:28 history edited Tomerikoo CC BY-SA 4.0
deleted 9 characters in body; edited title
Nov 18, 2020 at 15:19 answer added peter554 timeline score: 1
Nov 18, 2020 at 15:15 comment added Niloct You're almost there. The or expression is wrong. Do 2 for loops, one for the rows, other nested for the columns, and check if the current position is different from 1, -1 or 0.
Nov 18, 2020 at 15:12 history asked Pedro CC BY-SA 4.0