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Questions tagged [time-evolution]

The quantum mechanical time evolution operator governs how observables and/or states evolve during finite time steps, and is always unitary. Use this tag for questions about the time evolution operator, or the different equations of motion in the Schrödinger/Heisenberg/Dirac pictures. For time-independent Hamiltonians, the time evolution operator is simply exp(-iHt).

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Newton's Laws can be presented as a statement regarding the acceleration and time evolution of objects: $$\ddot {\bf x} = F(\dot {\bf x},{\bf x}) $$ In other words, the time evolution of a physical ...
Nathaniel Bubis's user avatar
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2 answers
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Given two bosonic operators $A$, $B$ (in the Heisenberg picture) in a QFT, the time-ordered product of $A$ and $B$ is defined as $$ T\{A(t_1)B(t_2)\}=\theta(t_1-t_2)A(t_1)B(t_2)+\theta(t_2-t_1)B(t_2)A(...
Hezaraki 's user avatar
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On Chapter 7 of Fetter & Walecka, the authors prove Dyson formula for the (imaginary time) propagator $U(t,t_{0}) = e^{H_{0}t_{0}}e^{-H(t_{0}-t)}e^{-H_{0}t}$, where I am ommitting the $\hbar$'s. ...
InMathweTrust's user avatar
1 vote
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The conditions for adiabatic evolution is that for every possible $n$, we must have $$ \sum_{n\neq m}\frac{\langle n(t) | \dot{H} | m(t) \rangle }{E_n(t)-E_m(t)} \to 0$$ which is achievable either by ...
Ilya Iakoub's user avatar
1 vote
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Follow-up question to How to deal with explicit time dependence in the Heisenberg picture? Time evolution of an operator A (in Heisenberg picture) is given as: $$\frac{\mathrm{d}\hat{A}_H}{\mathrm{d}t}...
DarkMIR4GE's user avatar
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This might be a conceptual question more than a technical one, however it would be very useful to see different conceptual approaches to address this problem physically/mathematically. The question ...
BrightNeutrino's user avatar
5 votes
1 answer
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In the Schrödinger, Heisenberg, and interaction pictures, the time evolution of an operator $A$ is defined differently. In the $\textbf{Heisenberg picture}:$ \begin{equation} A_H(t) = e^{i(H_0 + V)t} ...
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I am trying to time evolve quantum systems in the presence of a gravitational potential. To do this I need a free localised 3+1 dimensional wave packet with velocity so that I can perturb with a weak ...
Edwin Beggs's user avatar
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The state of a quantum system at time $t$ is given by the orthonormal base states $k$ and $j$, with probability amplitudes: \begin{equation} C_k(t_0 + \Delta t) \: = \: \langle{k} \vert \psi(t_0) \...
Heathcliff's user avatar
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I've written the following proof: Let $A,B$ be observables (Hermitian operators). define $ ΔA:=A-<A> $. the uncertainty principle is: $$ ⟨(ΔA)^2⟩⟨(ΔB)^2⟩ ≥|⟨[A,B]⟩|^2/4 $$ The Heisenberg ...
Paolo Puscus's user avatar
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I am following the The Floquet Engineer’s Handbook (https://arxiv.org/pdf/2003.08252). The formula (36) in page 10 is trying to calculate the time evolution of the Floquet creation/anni. operator in ...
Yecheng Jing's user avatar
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In wave mechanics, the time evolution equation is given as $$ i \hbar \frac{\partial}{\partial t} \psi(\vec{r},t)= \hat{H} \psi(\vec{r},t) $$ Here $\psi(\vec{r},t)$ is a function from space and time ...
user370848's user avatar
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1 answer
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Suppose the potential of the quantum particle is time dependent , $V(x,t)$ . Therefore the hamiltonian can be written as :- $$\hat H=-\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x^2}+V(x,t)$$ And we ...
Reader's user avatar
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In Minkowski space, the KG Lagrangian is time translation invariant. The corresponding Noether charge is the Hamiltonian. Because this is a symmetry it is generated by a unitary operator $$|\psi\...
Toby Peterken's user avatar
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2 answers
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In optics, we often use the complex amplitude to specify the electric and magnetic fields at any instant. A rightward-propagating plane wave can be expressed as $$ \exp(ikz) $$ and $$ \exp(-ikz) $$ is ...
L.Han's user avatar
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