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18 hours ago vote accept Hezaraki
18 hours ago comment added Hezaraki Hi, @Qmechanic, thank you for your continuous attention to this problem. Your latest update looks correct and inspires me a lot. However, after accepting your logic, I have one more quick question: how do I return to the Schrodinger picture if the picture-changing operators I apply to every operator (in the Heisenberg picture) are the same? Anyway, I will accept this answer.
20 hours ago history edited Qmechanic CC BY-SA 4.0
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yesterday history edited Qmechanic CC BY-SA 4.0
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yesterday history edited Qmechanic CC BY-SA 4.0
Added explanation
yesterday history edited Qmechanic CC BY-SA 4.0
Added explanation
yesterday history edited Qmechanic CC BY-SA 4.0
Minor formatting
yesterday history answered Qmechanic CC BY-SA 4.0