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Added explanation
Source Link
cole
  • 4k
  • 1
  • 14
  • 26

<> (Safe)


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

Explanation and##Explanation:

Here's the source coming sooncode (15 bytes):

f1-:0(?;::0g*n!

f pushes 15 (our counter) onto the stack (this is skipped by the ! at the end so as not to push more than one counter)

1- subtracts 1 from the counter

:0(?; The frowny face tests if the counter is less than 0, the rest ends the program if it is

:: Duplicates the counter twice

0g Grabs the character at the point (c,0) in the source code where c is the counter

* Multiplies the second duplicate of the counter by the ASCII representation of the character previously grabbed

n Prints the result.

So, split up, the output is [462, 1430, 504, 1133, 480, 522, 464, 413, 378, 200, 192, 174, 90, 49, 0]. This corresponds to the ASCII interpretation of the code in reverse multiplied by the numbers 14 to 0 (i.e. [!*14, n*13, ... f*0]).

Probably the hardest part about cracking this would be figuring out how to split up the numbers correctly, but if you get the right ones it's just a matter of trying things until you get something that works.

<> (Safe)


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

Explanation and source coming soon.

<> (Safe)


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

##Explanation:

Here's the source code (15 bytes):

f1-:0(?;::0g*n!

f pushes 15 (our counter) onto the stack (this is skipped by the ! at the end so as not to push more than one counter)

1- subtracts 1 from the counter

:0(?; The frowny face tests if the counter is less than 0, the rest ends the program if it is

:: Duplicates the counter twice

0g Grabs the character at the point (c,0) in the source code where c is the counter

* Multiplies the second duplicate of the counter by the ASCII representation of the character previously grabbed

n Prints the result.

So, split up, the output is [462, 1430, 504, 1133, 480, 522, 464, 413, 378, 200, 192, 174, 90, 49, 0]. This corresponds to the ASCII interpretation of the code in reverse multiplied by the numbers 14 to 0 (i.e. [!*14, n*13, ... f*0]).

Probably the hardest part about cracking this would be figuring out how to split up the numbers correctly, but if you get the right ones it's just a matter of trying things until you get something that works.

Labelled as safe
Source Link
cole
  • 4k
  • 1
  • 14
  • 26

<> (Safe)


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

Explanation and source coming soon.

<>


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

<> (Safe)


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?

Explanation and source coming soon.

Source Link
cole
  • 4k
  • 1
  • 14
  • 26

<>


Tested on the online and official interpreters.

Range: <= 16

String: 4621430504113348052246441337820019217490490

This is pretty 1337, huh?